How many times does the long hand of the clock pass the short hand between midnight one day and midnight the next day? Since the two hands are together at the stroke of midnight, it does not count as passing.

Assuming we have a 12-hour clock with hands, I believe that in 24 hours the hands will pass 22 or 23 times, depending on whether we count midnight only once or twice.

1st meeting - start - midnight

11 meetings until noon:
By design, the hands meet every hour, but at 11 o'clock, that would be after 11:55, so they won't be able to meet until 12:00, whether it's noon or midnight, so that's 11 meetings for 12 hours .

from noon to midnight - 10 or 11 meetings.
Just like before, there will be 11 meetings, the only question is, do we count the last meeting at midnight of the next day as well? If so, it will be 23 meetings, or 22.

The long hand of a clock will pass the short hand 12 times in a day.

21 times. We do not count starting and ending midnight.

12

Trick question, 22 times overlap but pass 21

In one day, the long hand of the clock will move 360 degrees (a full turn), and the short hand of the clock will also move 360 degrees (a full turn). Thus, in one day, both hands will have one complete passing. Next, note that there are 24 hours in a day between two consecutive hours. So if you have to go through one complete revolution in a day, then you have to go through one 24th part (1/24) of a full circle in an hour. Since there are 24 hours between two consecutive midnights, the long hand of a clock must travel 1/24 of a full turn to reach the next midnight. So the answer is: the long hand of a clock passes the short hand once every 24 hours, which is once a day.